Problem 9

Problem Statement :Problem9

Algorithm:
We  solve the two given equations in the problem ie

• a² + b² = c²
• a + b + c = 1000

This leads to value of  b = (1000000 - 2000 * a) /  (2000 - 2 * a).

The remaining part is olved by iterating over 1000 values of a using the above value of b and checking for c.

Solution:

public class problem9 {
 public static void main(String args[]) {
  for (int a = 999; a >= 1; a--) {
   double b = (1000000 - 2000 * a) / (double) (2000 - 2 * a);
   if ((a * a + b * b) == (1000 - a - b) * (1000 - a - b) && a != b
     && (b - (int) b) == 0 && b > 0)
    System.out.println(a * b * (1000 - a - b));
  }
 }
}